CALENDER-IQ SOLVE PROBLEM
· Odd Days:
We are supposed to find the day of
the week on a given date.
For this, we use the concept of 'odd
days'.
In a given period, the number of
days more than the complete weeks are called odd days.
· Leap Year:
(i). Every year divisible by 4 is a
leap year, if it is not a century.
(ii). Every 4th century
is a leap year and no other century is a leap year.
Note: A leap year has 366 days.
Examples:
- Each of the years 1948, 2004, 1676 etc. is a leap year.
- Each of the years 400, 800, 1200, 1600, 2000 etc. is a
leap year.
- None of the years 2001, 2002, 2003, 2005, 1800, 2100 is
a leap year.
· Ordinary Year:
The year which is not a leap year is
called an ordinary years. An ordinary year has 365 days.
· Counting of Odd Days:
- 1 ordinary year = 365 days = (52 weeks + 1 day.)
1 ordinary year has 1 odd day.
- 1 leap year = 366 days = (52 weeks + 2 days)
1 leap year has 2 odd days.
- 100 years = 76 ordinary years + 24 leap years
= (76
x 1 + 24 x 2) odd days = 124 odd days.
= (17
weeks + days) 5 odd days.
Number of odd days in 100 years = 5.
Number of
odd days in 200 years = (5 x 2) 3 odd days.
Number of
odd days in 300 years = (5 x 3) 1 odd day.
Number of
odd days in 400 years = (5 x 4 + 1) 0 odd day.
Similarly,
each one of 800 years, 1200 years, 1600 years, 2000 years etc. has 0 odd days.
· Day of the Week Related to Odd Days:
No. of days: |
0 |
1 |
2 |
3 |
4 |
5 |
6 |
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Day: |
Sun. |
Mon. |
Tues. |
Wed. |
Thurs. |
Fri. |
Sat. |
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1. |
It was Sunday on Jan 1, 2006. What
was the day of the week Jan 1, 2010? |
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Answer: Option C Explanation: On 31st December, 2005
it was Saturday. Number of odd days from the year
2006 to the year 2009 = (1 + 1 + 2 + 1) = 5 days.
Thus, on 1st Jan, 2010
it is Friday. |
2. |
What was the day of the week on 28th
May, 2006? |
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Answer: Option D Explanation: 28 May, 2006 = (2005 years +
Period from 1.1.2006 to 28.5.2006) Odd days in 1600 years = 0 Odd days in 400 years = 0 5 years = (4 ordinary years + 1
leap year) = (4 x 1 + 1 x 2) Jan. Feb. March
April May (31 + 28 +
31 + 30
+ 28 ) = 148 days
Total number of odd days = (0 + 0
+ 6 + 1) = 7 Given day is Sunday. |
3. |
What was the day of the week on 17th
June, 1998? |
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|
4. |
What will be the day of the week
15th August, 2010? |
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Answer: Option A Explanation: 15th August, 2010 =
(2009 years + Period 1.1.2010 to 15.8.2010) Odd days in 1600 years = 0 Odd days in 400 years = 0 9 years = (2 leap years + 7
ordinary years) = (2 x 2 + 7 x 1) = 11 odd days Jan. Feb. March
April May June
July Aug. (31 + 28 +
31 + 30
+ 31 + 30
+ 31 + 15) = 227 days
Total number of odd days = (0 + 0
+ 4 + 3) = 7 Given day is Sunday. |
5. |
Today is Monday. After 61 days, it
will be: |
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Answer: Option B Explanation: Each day of the week is repeated
after 7 days. So, after 63 days, it will be
Monday.
|
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|
If 6th March, 2005 is
Monday, what was the day of the week on 6th
March, 2004? |
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Answer: Option A Explanation: The year 2004 is a leap year. So,
it has 2 odd days. But, Feb 2004 not included because
we are calculating from March 2004 to March 2005. So it has 1 odd day only.
Given that, 6th March,
2005 is Monday.
|
7. |
On what dates of April, 2001 did
Wednesday fall? |
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Answer: Option D Explanation: We shall find the day on 1st
April, 2001. 1st April, 2001 = (2000
years + Period from 1.1.2001 to 1.4.2001) Odd days in 1600 years = 0 Odd days in 400 years = 0 Jan. Feb. March April Total number of odd days = (0 + 0
+ 0) = 0 On 1st April, 2001 it
was Sunday. In April, 2001 Wednesday falls on
4th, 11th, 18th and 25th. |
8. |
How many days are there in x
weeks x days? |
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Answer: Option B Explanation: x weeks x days = (7x + x) days = 8x
days. |
9. |
The last day of a century cannot
be |
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Answer: Option C Explanation: 100 years contain 5 odd days.
200 years contain (5 x 2)
300 years contain (5 x 3) = 15
400 years contain 0 odd day.
This cycle is repeated.
|
10. |
On 8th Feb, 2005 it was
Tuesday. What was the day of the week on 8th Feb, 2004? |
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Answer: Option C Explanation: The year 2004 is a leap year. It
has 2 odd days.
Hence, this day is Sunday. |
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11. |
The calendar for the year 2007
will be the same for the year: |
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Answer: Option D Explanation: Count the number of odd days from
the year 2007 onwards to get the sum equal to 0 odd day. Year : 2007 2008
2009 2010 2011 2012 2013 2014 2015 2016 2017 Odd day : 1
2 1 1
1 2 1
1 1 2
1 Sum = 14 odd days
|
12. |
Which of the following is not a
leap year? |
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Answer: Option A Explanation: The century divisible by 400 is a
leap year.
|
13. |
On 8th Dec, 2007
Saturday falls. What day of the week was it on 8th Dec, 2006? |
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Answer: Option D Explanation: The year 2006 is an ordinary year.
So, it has 1 odd day. So, the day on 8th Dec,
2007 will be 1 day beyond the day on 8th Dec, 2006. But, 8th Dec, 2007 is
Saturday.
|
14. |
January 1, 2008 is Tuesday. What
day of the week lies on Jan 1, 2009? |
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Answer: Option C Explanation: The year 2008 is a leap year. So,
it has 2 odd days. 1st day of the year
2008 is Tuesday (Given) So, 1st day of the year
2009 is 2 days beyond Tuesday. Hence, it will be Thursday. |
15. |
January 1, 2007 was Monday. What
day of the week lies on Jan. 1, 2008? |
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Answer: Option B Explanation: The year 2007 is an ordinary year.
So, it has 1 odd day. 1st day of the year
2007 was Monday. 1st day of the year
2008 will be 1 day beyond Monday. Hence, it will be Tuesday. |
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